2x^2=2(11x-48)

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Solution for 2x^2=2(11x-48) equation: 



2x^2=2(11x-48)

We move all terms to the left:

2x^2-(2(11x-48))=0



We calculate terms in parentheses: -(2(11x-48)), so:

2(11x-48)

We multiply parentheses

22x-96

Back to the equation:

-(22x-96)



We get rid of parentheses

2x^2-22x+96=0

a = 2; b = -22; c = +96;
Δ = b2-4ac
Δ = -222-4·2·96
Δ = -284
Delta is less than zero, so there is no solution for the equation

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